Modi to unveil 216-ft 'Statue of Equality' in Hyd on 5 Feb
During his visit to the city, the PM will also visit the ICRISAT campus in Patancheru, Hyderabad, and kick start the 50th-anniversary celebrations of ICRISAT.
By Newsmeter Network Published on 3 Feb 2022 10:51 AM GMT
Hyderabad: Prime Minister Narendra Modi will unveil the 216-feet tall "Statue of Equality" in Hyderabad on 5 February to commemorate the 11th-century Bhakti Saint Sri Ramanujacharya.
The statue is made of 'panchaloha', a combination of five metals ā gold, silver, copper, brass, and zync. It is among one of the world's tallest metallic statues in a sitting position. It is mounted on a 54-ft high base building named 'Bhadra Vedi'. It has floors devoted to a Vedic digital library and research centre, ancient Indian texts, a theatre, an educational gallery detailing many works of Sri Ramanujacharya. The statue has been conceptualised by Sri Chinna Jeeyar Swami of Sri Ramanujacharya Ashram.
During the unveiling ceremony, a 3D presentation on the life, journey, and teaching of Sri Ramanujacharya will also be showcased. Mr. Modi will also visit the recreations of 108 Divya Desams (ornately carved temples) that surround the statue.
The inauguration of the Statue of Equality is part of the 12-day Sri Ramanuja Sahasrabdi Samaroham, the ongoing 1,000th birth anniversary celebrations of Sri Ramanujacharya.
During his visit to the city, the Prime Minister will also visit the International Crops Research Institute for the Semi-Arid Tropics (ICRISAT) campus in Patancheru, Hyderabad, and kick start the 50th-anniversary celebrations of ICRISAT. Mr. Modi will inaugurate ICRISAT's Climate Change Research Facility on Plant Protection and the Rapid Generation Advancement Facility. The Prime Minister will also unveil a specially designed logo of ICRISAT and launch a commemorative stamp issued on the occasion.
